Bromoethane CAS 74-96-4
1-Bromobutane CAS 109-65-9
21 9 月, 2020Methanesulfonic acid CAS 75-75-2
18 9 月, 2020
Bromoethane Properties
| Product name | Bromoethane |
| Synonyms | 1-Bromethan;Bromethan;JACS-74-96-4;SINOBIO;ETHYL BROMIDE extrapure;Bromoethane, 98%, pure;Bromoethane, 99+%, extra pure;Bromoethane, extra pure |
| Cas | 74-96-4 |
| MF | C2H5Br |
| MW | 108.9651 |
| EINECS | 200-825-8 |
| Product Categories | Biochemical reagents; Organic chemical raw materials; Chemical products-organic chemical industry; Halogenate compounds; Organic block; Organic solvent; Other biochemical reagents; Organic bromide; pharmaceutical intermediates; intermediates; organics; alkyl bromides; monofunctional & alpha,omega-bifunctional alkanes; monofunctional alkanes; pharmaceutical intermediate; Intermediate; Reagents; bromide |
| Melting point | -119 °C |
| Boiling point | 37-40 °C(lit.) |
| Density | 1.46 g/mL at 25 °C(lit.) |
| storage temp. | Store at RT. |
| form | powder |
| Brand Name | Fousi Chemical |
Bromoethane Usage
Used in medicine, pesticide and dye industries, it is an ethylating agent in organic synthesis and also used as refrigerant and organic solvent
Bromoethane Packaging and Shipping
Packaging:25kg/ bag, customer’s request
Shipping:It can be according to the customer’s request
Bromoethane Storage
Store at RT.
Bromoethane hydrolysis
C2H5Br+H2O→CH3CH2OH+HBr (reaction condition is an aqueous solution of sodium hydroxide)
The essence of the elimination reaction of bromoethane
CH3CH2Br–→CH2=CH2↑+HBr
The reaction condition is an alcohol solution of sodium hydroxide (usually ethanol), that is, NaOH/alcohol
In some cases, the reaction of HBr and NaOH can also be added.
Namely: CH3CH2Br+NaOH—→CH2=CH2↑+NaBr+H2O
The condition is also in alcohol solution.
NaOH is not a catalyst, but a reactant involved in the reaction. The elimination first produces HBr, NaOH+HBr=NaBr+H2O, which is neutralized by NaOH, so NaOH is the reactant, and ethanol is the catalyst.
The reaction mechanism is as follows:
CH3CH2-X + :B → CH3CH(Br)-H…B Attacks β-hydrogen by a strong base to form a transition state.
CH3CH(Br)-H…B → CH2=CH2 + HB The bond breaks, and at the same time a carbon-carbon double bond is formed.